最近在qq群经常看到一个题目，网上查找资料发现，有人实现了一半内容，都是在处理0的问题上卡住了，自己就尝试用刚开始学习的python写了一下。python处理这个问题还是比较方便。
题目：
代码：
#!/usr/bin/env python# -*- coding: utf-8 -*-#转换import rechd = {' ':'m','0':'零','1':'壹','2':'贰','3':'叁','4':'肆','5':'伍','6':'陆','7':'柒','8':'捌','9':'玖'}und = {'S':'拾','B':'佰','Q':'仟','W':'万','Y':'亿'}#判断输入内容(首位不为零的整数)ips = raw_input('Please input a number: ')while ips[0] == '0': ips = raw_input('Wrong,the first non-zero: ')else: while ips.isdigit(): break else: ips = raw_input('Wrong,please input a number: ')if len(ips) <= 9: #输出9位字符，右对齐，补空格 ips = ips.rjust(9) #转换成大写 ops = chd[ips[0]]+und['Y']+chd[ips[1]]+und['Q']+chd[ips[2]]+und['B']+chd[ips[3]]+und['S']+chd[ips[4]]+und['W']+chd[ips[5]]+und['Q']+chd[ips[6]]+und['B']+chd[ips[7]]+und['S']+chd[ips[8]]+'元' #无用的数字位替换为空 ops = re.sub('(m...)+','',ops) #处理零 ops = re.sub('零元$','元',ops) ops = re.sub('零万','万',ops) ops = re.sub('(零...)+','零',ops) ops = re.sub('零万','万',ops) ops = re.sub('零元$','元',ops) print opselse: print 'The number is too big.' 测试发现正则部分不全面，修改如下：
#!/usr/bin/env python# -*- coding: utf-8 -*-#转换import rechd = {' ':'m','0':'零','1':'壹','2':'贰','3':'叁','4':'肆','5':'伍','6':'陆','7':'柒','8':'捌','9':'玖'}und = {'S':'拾','B':'佰','Q':'仟','W':'万','Y':'亿'}#判断输入内容(首位不为零的整数)ips = raw_input('Please input a number: ')while ips[0] == '0': ips = raw_input('Wrong,the first non-zero: ')else: while ips.isdigit(): break else: ips = raw_input('Wrong,please input a number: ')if len(ips) <= 9: #输出9位字符，右对齐，补空格 ips = ips.rjust(9) #转换成大写 ops = chd[ips[0]]+und['Y']+chd[ips[1]]+und['Q']+chd[ips[2]]+und['B']+chd[ips[3]]+und['S']+chd[ips[4]]+und['W']+chd[ips[5]]+und['Q']+chd[ips[6]]+und['B']+chd[ips[7]]+und['S']+chd[ips[8]]+'元' #无用的数字位替换为空 ops = re.sub('(m...)+','',ops) #处理零 ops = re.sub('零元$','元',ops) ops = re.sub('零万','万',ops) ops = re.sub('(零...)+','零',ops) ops = re.sub('亿零万','亿零',ops) ops = re.sub('零万','万',ops) ops = re.sub('零元$','元',ops) ops = re.sub('亿零元$','亿元',ops) print opselse: print 'The number is too big.'